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Home > Art, Film & Photography > The Mechanic's Assistant; A Thorough Practical Treatise on Mensuration and the Sliding Rule: Teaching the Manner of Drawing All Regular Superficies, and the Contents of All Regular Solids, Both by Numbers and by the Sliding Rule. Treating
The Mechanic's Assistant; A Thorough Practical Treatise on Mensuration and the Sliding Rule: Teaching the Manner of Drawing All Regular Superficies, and the Contents of All Regular Solids, Both by Numbers and by the Sliding Rule. Treating

The Mechanic's Assistant; A Thorough Practical Treatise on Mensuration and the Sliding Rule: Teaching the Manner of Drawing All Regular Superficies, and the Contents of All Regular Solids, Both by Numbers and by the Sliding Rule. Treating


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About the Book

This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1849 edition. Excerpt: ...311.51 ale, and 380.29 wine gallons. When the diameter of the segment's base and its height are given, to find the diameter of the sphere: --Divide the square of the radius of the base by the height, and to the quotient add the height. See 24, page 82. The solidity of a spherical segment is equal to that of half of its least circumscribing cylinder, plus the solidity of a sphere whose diameter is equal to the height of the segment. Therefore, To gauge a spherical segment: --Find the contents of one-half of its least circumscribing cylinder, and the contents of a sphere whose diameter is equal to the height of the segment, and the sum of their contents will be the solidity of the spherical segment. 12. What is the solidity of a spherical segment, whose height is 4 feet, and the diameter of its base 16 feet? Ans. 435.635 feet. Place 2 feet over 13.54 on D, the gauge point for feet in a cylinder, and over 192, the diameter of the segment's base La inches, you will find 3Q2.3 feet, the solidity of one-half the least circumscribing cylinder; then place 4 feet over 16.58, the gauge point for feet in a sphere, and over 48, the height of the segment in inches, you will find 33.4 feet, which, being added to 302.3, equals 435.7 feet for the solidity of the segment. 1 47. SPHERICAL ZONR A spherical zone is the frustum of a sphere formed by cutting off two segments by planes parallel to each other. 1. To find the solidity of a spherical zone: --Subtract the solidity of the two segments from the solidity of the whole sphere, and the remainder will be the solidity of the zone. Or, 2. Add together the squares of the radii of the two ends, and one-third of the square of the height, which sum multiply by the height, and this product by 1.5708, and the result will be...


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Product Details
  • ISBN-13: 9781236358578
  • Publisher: Rarebooksclub.com
  • Publisher Imprint: Rarebooksclub.com
  • Height: 246 mm
  • No of Pages: 72
  • Spine Width: 4 mm
  • Weight: 145 gr
  • ISBN-10: 1236358570
  • Publisher Date: 01 Jun 2012
  • Binding: Paperback
  • Language: English
  • Returnable: N
  • Sub Title: Teaching the Manner of Drawing All Regular Superficies, and the Contents of All Regular Solids, Both by Numbers and by the Sliding Rule. Treating
  • Width: 189 mm


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The Mechanic's Assistant; A Thorough Practical Treatise on Mensuration and the Sliding Rule: Teaching the Manner of Drawing All Regular Superficies, and the Contents of All Regular Solids, Both by Numbers and by the Sliding Rule. Treating
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The Mechanic's Assistant; A Thorough Practical Treatise on Mensuration and the Sliding Rule: Teaching the Manner of Drawing All Regular Superficies, and the Contents of All Regular Solids, Both by Numbers and by the Sliding Rule. Treating
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The Mechanic's Assistant; A Thorough Practical Treatise on Mensuration and the Sliding Rule: Teaching the Manner of Drawing All Regular Superficies, and the Contents of All Regular Solids, Both by Numbers and by the Sliding Rule. Treating

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